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Practice · HKDSE Mathematics Compulsory Part · Paper 1 long questions

Revising this topic? Also work the Paper 2 multiple-choice.

Equations of Straight Lines — Paper 1 Long Questions

Eight original long questions on coordinate geometry of the straight line, written to match the shape and difficulty of HKDSE Paper 1. They run from a four-mark warm-up on the two-point form up to an eleven-mark question where the answer stays in terms of m. Final answers are on the page. Detailed solutions can be requested by email.

8 questions · about 75 minutes, 61 marks · answers below each question

All questions are original, written for Math and AI Academy and modelled on past-paper style. They are not reproductions of HKEAA examination questions.

Question 1 · Modelled on 2026 P1 Q12(a) · 4 marks

The straight line L1L_1 passes through the points A(3,8)A(-3,\,8) and B(5,4)B(5,\,-4).

(a)  Find the equation of L1L_1. (2 marks)

(b)  The straight line L2L_2 passes through the origin and is parallel to L1L_1. Find the equation of L2L_2. (2 marks)

Show answer

(a)  3x+2y7=03x + 2y - 7 = 0

(b)  3x+2y=03x + 2y = 0

Final answers only. Detailed solutions can be requested by email.

Question 2 · Modelled on 2023 P2 Q10 and 2018 P2 Q26 · 5 marks

The straight line L:2x5y+k=0L : 2x - 5y + k = 0, where kk is a positive constant, cuts the xx-axis at AA and cuts the yy-axis at BB. Denote the origin by OO. It is given that the area of OAB\triangle OAB is 4545.

(a)  Express the coordinates of AA and of BB in terms of kk. (2 marks)

(b)  Find kk. (3 marks)

Show answer

(a)  A(k2,0)A\left(-\dfrac{k}{2},\,0\right), B(0,k5)B\left(0,\,\dfrac{k}{5}\right)

(b)  k=30k = 30

Final answers only. Detailed solutions can be requested by email.

Question 3 · Modelled on 2019 P2 Q23 · 7 marks

In the figure, the straight line L1:ax+by+12=0L_1 : ax + by + 12 = 0 cuts the xx-axis at (4,0)(-4,\,0) and cuts the yy-axis at (0,6)(0,\,6), where aa and bb are constants.
Figure for question 3

(a)  Find aa and bb. (3 marks)

(b)  The straight line L2L_2 is perpendicular to L1L_1 and passes through (0,6)(0,\,6). L2L_2 cuts the xx-axis at CC. Find the coordinates of CC. (2 marks)

(c)  Find the area of the triangle bounded by L1L_1, L2L_2 and the xx-axis. (2 marks)

Show answer

(a)  a=3a = 3, b=2b = -2

(b)  C(9,0)C(9,\,0)

(c)  3939

Final answers only. Detailed solutions can be requested by email.

Question 4 · Modelled on 2022 P2 Q18 · 7 marks

The equations of the straight lines L1L_1, L2L_2 and L3L_3 are x+2y8=0x + 2y - 8 = 0, 3xy3=03x - y - 3 = 0 and kx+y11=0kx + y - 11 = 0 respectively, where kk is a constant.

(a)  Find the coordinates of the point of intersection PP of L1L_1 and L2L_2. (3 marks)

(b)  It is given that L1L_1, L2L_2 and L3L_3 are concurrent. Find kk. (2 marks)

(c)  Find the equation of the straight line which passes through PP and whose xx-intercept and yy-intercept are equal and non-zero. (2 marks)

Show answer

(a)  P(2,3)P(2,\,3)

(b)  k=4k = 4

(c)  x+y5=0x + y - 5 = 0

Final answers only. Detailed solutions can be requested by email.

Question 5 · Modelled on 2026 P2 Q26 and 2020 P1 Q14(b) · 8 marks

The equations of the straight lines L1L_1 and L2L_2 are 3x4y+12=03x - 4y + 12 = 0 and 3x4y36=03x - 4y - 36 = 0 respectively.

(a)  Someone claims that L1L_1 and L2L_2 are parallel. Do you agree? Explain your answer. (2 marks)

(b)  PP is a moving point in the rectangular coordinate plane such that the perpendicular distance from PP to L1L_1 is equal to the perpendicular distance from PP to L2L_2. Describe the locus of PP and find its equation. (3 marks)

(c)  The locus of PP cuts the xx-axis at AA and cuts the yy-axis at BB. Find ABAB and the area of OAB\triangle OAB, where OO is the origin. (3 marks)

Show answer

(a)  Agree. Both slopes are 34\dfrac{3}{4} and the yy-intercepts differ.

(b)  The locus is the straight line midway between L1L_1 and L2L_2: 3x4y12=03x - 4y - 12 = 0

(c)  AB=5AB = 5; area =6= 6

Final answers only. Detailed solutions can be requested by email.

Question 6 · Modelled on 2015 P1 Q14(a) and 2023 P2 Q26 · 9 marks

The coordinates of the points AA and BB are (6,3)(-6,\,3) and (4,7)(4,\,-7) respectively. PP is a moving point in the rectangular coordinate plane such that AP=BPAP = BP. Denote the locus of PP by Γ\Gamma.

(a)  Find the equation of Γ\Gamma. (3 marks)

(b)  Γ\Gamma cuts the straight line x+2y7=0x + 2y - 7 = 0 at QQ. Find the coordinates of QQ. (3 marks)

(c)  Find the area of ABQ\triangle ABQ. (3 marks)

Show answer

(a)  xy1=0x - y - 1 = 0

(b)  Q(3,2)Q(3,\,2)

(c)  4040

Final answers only. Detailed solutions can be requested by email.

Question 7 · Modelled on 2016 P1 Q20 and 2023 P1 Q19 · 10 marks

In the figure, the coordinates of the points AA, BB and CC are (2,6)(-2,\,6), (7,3)(7,\,3) and (2,2)(2,\,-2) respectively.
Figure for question 7

(a)  Find the equation of the perpendicular bisector of ABAB. (3 marks)

(b)  Find the equation of the perpendicular bisector of BCBC. (2 marks)

(c)  Hence find the coordinates of the circumcentre DD of ABC\triangle ABC. (3 marks)

(d)  Is DD an interior point of ABC\triangle ABC? Explain your answer. (2 marks)

Show answer

(a)  3xy3=03x - y - 3 = 0

(b)  x+y5=0x + y - 5 = 0

(c)  D(2,3)D(2,\,3)

(d)  Yes. AB2=90AB^2 = 90, BC2=50BC^2 = 50, CA2=80CA^2 = 80; every angle is acute, so the circumcentre lies inside.

Final answers only. Detailed solutions can be requested by email.

Question 8 · Modelled on 2024 P1 Q12(a) · 11 marks

In the figure, the straight line L1:y=mxL_1 : y = mx, where m>0m > 0, and the straight line L2:x+y6=0L_2 : x + y - 6 = 0 intersect at PP. L2L_2 cuts the xx-axis at AA and cuts the yy-axis at BB. Denote the origin by OO.
Figure for question 8

(a)  Write down the coordinates of AA and of BB. (2 marks)

(b)  Express the coordinates of PP in terms of mm. (3 marks)

(c)  Express the area of OAP\triangle OAP and the area of OBP\triangle OBP in terms of mm. (3 marks)

(d)  It is given that the area of OAP:\triangle OAP : the area of OBP=2:1\triangle OBP = 2 : 1. Find mm. Hence write down AP:PBAP : PB. (3 marks)

Show answer

(a)  A(6,0)A(6,\,0), B(0,6)B(0,\,6)

(b)  P(6m+1, 6mm+1)P\left(\dfrac{6}{m+1},\ \dfrac{6m}{m+1}\right)

(c)  Area of OAP=18mm+1\triangle OAP = \dfrac{18m}{m+1}; area of OBP=18m+1\triangle OBP = \dfrac{18}{m+1}

(d)  m=2m = 2; AP:PB=2:1AP : PB = 2 : 1

Final answers only. Detailed solutions can be requested by email.

Revising this topic? Also work the Paper 2 multiple-choice.

Where this sits in the syllabus

Equations of straight lines sits in the Measures, Shape and Space strand. It is the language every later coordinate topic is written in: equations of circles, loci and linear programming all assume you can move between a slope, two points and a general-form equation without thinking about it. Most marks lost here are lost on signs, not on method.

Full coverage of this topic, and the rest of the course, is on the Mathematics page. More sets are listed on the practice index.

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